Latihan Soal Aritmetika & Geometri , Tolong di bantu ya
Jawaban:
1. U3=24 -> a + 2b=24 (pers 1)
U6=36 -> a + 5b=36 (pers 2)
eliminasi pers 1 dan pers 2 menjadi
-3b= -12
b= 4
substitusi pers 1
a + 2.(4) = 24
a + 8 = 24
a= 16
a. U12= 16 + 11.(4) = 60
b. U15= 16 + 14.(4) = 72
S15= 15/2 (16 + 72) = 15/2 (88) = 660
2. U8 =20 -> a + 7b =20 (pers 1)
U5 =25 -> a + 4b =25 (pers 2)
eliminasi pers 1 dan pers 2
3b =-5
b= -5/3
substitusi pers 1
a + 7 (-5/3) =20
a + -35/3 =20
a= 20 + 35/3
a= 60/3 + 35/3 = 95/3
a. U14 = 95/3 + 13. (-5/3)
=95/3 - 65/3 = 30/3 = 10
b. U12= 95/3 + 11. (-5/3) = 40/3
S12= 12/2 (95/3 + 40/3)
= 6 (135/3) =270
Penjelasan dengan langkah-langkah:
maaf ya cma ngisi no 1 bagian a
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